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2x^2-4349x+101466=0
a = 2; b = -4349; c = +101466;
Δ = b2-4ac
Δ = -43492-4·2·101466
Δ = 18102073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4349)-\sqrt{18102073}}{2*2}=\frac{4349-\sqrt{18102073}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4349)+\sqrt{18102073}}{2*2}=\frac{4349+\sqrt{18102073}}{4} $
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